y^-4y=16

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Solution for y^-4y=16 equation: 



y^-4y=16

We move all terms to the left:

y^-4y-(16)=0

We add all the numbers together, and all the variables

-3y-16=0

We move all terms containing y to the left, all other terms to the right

-3y=16

y=16/-3

y=-5+1/3

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